Which the the following includes The greatest variety of representative particles: 1 mole the water molecules, 1 mole that copper ato

**derekwadsworth.com:**

1 mole of salt chloride ions

**Explanation:**

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Gold has actually a molar massive of 197.0 g/mol. What is the concentration of yellow in seawater in moles per liter?(please show work)

**derekwadsworth.com:**

Since friend didnt get asked for a spefic weight of gold lets assume it to be 5g

**Explanation:**

5g Au/197 =.02538 mols in 1 liter the sea water is

.02538/1L which offers you a Molarity the .012538 presume 5g if they ask for a different number just replace 5 with any weight in grams

What massive of salt benzoate should be included to 160.0 ml the a 0.17 m benzoic acid solution in order to obtain a buffer through a ph

**derekwadsworth.com :**

**The mass of sodium benzoate that have the right to be added to benzoic acid is 5.07 g**

**Explanation :**

The trouble can be solved with the help of **Henderson-Hasselbalch equation.You are watching: Stromatolites are _____.**

**Step 1 : uncover concentration of salt benzoate**

The equation is provided below.

}We have been given,

**pH = 4.30**

Ka of benzoic acid can be discovered out using standard reference table i m sorry is 6.5 x 10⁻⁵

pKa = - log (Ka)

pKa = - log (6.5 x 10⁻⁵)

**pKa = 4.19 **

Let us plug in the above values in Henderson equation.

}(0.17M) " alt=" 4.30 = 4.19 + log in \fracThe functions

cancel the end each other.}0.17 " alt=" 10^0.11 = \fracThe base in this situation is salt benzoate.

**Therefore concentration of salt benzoate is 0.22 M.**

**Step 2 : find moles of sodium benzoate**

The volume of the solution is 160 mL.

Volume in l =

Moles of sodium benzoate deserve to be discovered as,

**Moles of sodium benzoate are 0.0352 **

**Step 3 : find mass of salt benzoate **

Mass of salt benzoate deserve to be calculate as

**Mass in grams = moles x Molar mass**

The formula of sodium benzoate is **C₇H₅O₂Na.See more: Emerald Graves Torches - Forum:Secret At The Lions Pavilion**

Molar massive of sodium benzoate = 7 x 12.01 + 5 x 1.01 + 2 x 16 + 22.98

**Molar mass of salt benzoate = 144.1 **

Mass of salt benzoate =

Mass of sodium benzoate = 5.07 g

**5.07 grams of salt benzoate have to be added to the provided volume the benzoic acid.**