Which the the following includes The greatest variety of representative particles: 1 mole the water molecules, 1 mole that copper ato
1 mole of salt chloride ions
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Gold has actually a molar massive of 197.0 g/mol. What is the concentration of yellow in seawater in moles per liter?(please show work)
Since friend didnt get asked for a spefic weight of gold lets assume it to be 5g
5g Au/197 =.02538 mols in 1 liter the sea water is
.02538/1L which offers you a Molarity the .012538 presume 5g if they ask for a different number just replace 5 with any weight in grams
What massive of salt benzoate should be included to 160.0 ml the a 0.17 m benzoic acid solution in order to obtain a buffer through a ph
The mass of sodium benzoate that have the right to be added to benzoic acid is 5.07 g
The trouble can be solved with the help of Henderson-Hasselbalch equation.
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Step 1 : uncover concentration of salt benzoate
The equation is provided below.
We have been given,
pH = 4.30
Ka of benzoic acid can be discovered out using standard reference table i m sorry is 6.5 x 10⁻⁵
pKa = - log (Ka)
pKa = - log (6.5 x 10⁻⁵)
pKa = 4.19
Let us plug in the above values in Henderson equation.
The base in this situation is salt benzoate.
Therefore concentration of salt benzoate is 0.22 M.
Step 2 : find moles of sodium benzoate
The volume of the solution is 160 mL.
Volume in l =
Moles of sodium benzoate deserve to be discovered as,
Moles of sodium benzoate are 0.0352
Step 3 : find mass of salt benzoate
Mass of salt benzoate deserve to be calculate as
Mass in grams = moles x Molar mass
The formula of sodium benzoate is C₇H₅O₂Na.
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Molar massive of sodium benzoate = 7 x 12.01 + 5 x 1.01 + 2 x 16 + 22.98
Molar mass of salt benzoate = 144.1
Mass of salt benzoate =
Mass of sodium benzoate = 5.07 g
5.07 grams of salt benzoate have to be added to the provided volume the benzoic acid.