R far from the nucleus such the its kinetic power is finally zero. And also so, we're offered a kinetic energy that the starts with, and also its final kinetic power will be zero. And, we require to figure out the place R such the this final kinetic energy is zero. Now, the change in kinetic power is going to be the opposite to the adjust in that potential energy, and also so it's going to be acquiring potential power as it gets closer and closer come this nucleus. And, that's going to be negative Q times the potential difference. So, the potential difference with infinity gift zero, is walk to be K Q end R, and also this resources Q is the charge in the yellow nucleus, and this small letter Q below is the fee of the alpha particle, which is 2 times the elementary school charge, because it is composed of two protons. So, we'll instead of K resources Q end R in location of V, and we have the change in kinetic energy then is an adverse little Q time K times funding Q split by R. And also so, we'll solve for R through mutiplying both political parties by R end Delta KE. And, we get this distance wherein it's close together it can gain to the nucleus. It's going to be an unfavorable little Q K capital Q divided by the last kinetic power minus the early kinetic energy. Now, the final kinetic power is zero. And, now we plugin numbers. So, us have negative two time 1.6 times ten to the minus 19 Coulombs, this is the fee in the alpha particle, times Coulomb's consistent times 79 time 1.6 times ten to the minus 19 Coulombs, i m sorry is the fee in the yellow nucleus, split by zero, last kinetic energy, minus 5.00 times ten come the six electron volts converted into Joules by multiply by 1.6 times ten come the minus 19 Joules every electron volts. And, we end up through 4.55 times ten to the minus 14 meters is the closest these alpha corpuscle can acquire to gold nuclei.">


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This is college Physics Answers through Shaun Dychko. And also now because that the particle that is composed of 2 protons through no electrons roughly them. So, essentially it"s the cell core of a helium atom. And, it"s pull close a yellow nucleus, which consists of 79 protons, and as it it s okay closer and closer, it is walking to it is in decelerating and getting slower and also slower as result of the repulsion indigenous the gold nucleus. And, it"ll reach a final position, the street R away from the nucleus such that its kinetic energy is finally zero. And so, we"re provided a kinetic energy that that starts with, and also its final kinetic energy will be zero. And, we require to figure out the position R such the this last kinetic power is zero. Now, the change in kinetic power is going to it is in the opposite to the readjust in the potential energy, and so it"s going come be gaining potential energy as it it s okay closer and closer to this nucleus. And, that"s going to be negative Q time the potential difference. So, the potential difference with infinity gift zero, is walk to be K Q over R, and this funding Q is the charge in the gold nucleus, and this small letter Q here is the charge of the alpha particle, i m sorry is two times the elementary school charge, due to the fact that it consists of 2 protons. So, we"ll instead of K resources Q end R in location of V, and we have actually the adjust in kinetic power then is an unfavorable little Q times K times funding Q separated by R. And so, we"ll resolve for R by mutiplying both political parties by R end Delta KE. And, we get this distance wherein it"s close as it can get to the nucleus. It"s going to be an adverse little Q K resources Q separated by the last kinetic energy minus the initial kinetic energy. Now, the final kinetic energy is zero. And, now we plugin numbers. So, us have an unfavorable two time 1.6 time ten to the minus 19 Coulombs, this is the charge in the alpha particle, times Coulomb"s continuous times 79 time 1.6 time ten come the minus 19 Coulombs, which is the charge in the gold nucleus, split by zero, final kinetic energy, minus 5.00 times ten come the 6 electron volts converted into Joules by multiply by 1.6 time ten come the minus 19 Joules per electron volts. And, we end up through 4.55 time ten come the minus 14 meter is the closest these alpha particles can get to gold nuclei.
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