a) $-4.80 \mathrmm / \mathrms$b) $t=3.41 \mathrms$c) $-28.4 \mathrmm / \mathrms$d) $1.28 \mathrmm$e) The graphs the $a_y, v_y,$ and also $y$ versus $t$ are given in figure $2.44 .$ take $y=0$ at the ground.




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Video Transcript

Okay, for this reason we have actually a hot air balloon increasing at five meters per 2nd at a height of fourty meters off the ground and also once in ~ a elevation of forty meters turn off the floor houses. Beanbag. We desire to uncover the place of this bean bag after ~ so unsure times. Therefore we first use place is a role of time equation for why Oh, Titian. At any type of time T is given by the early position. What's the initial velocity time? us one have acceleration times, time squared. Looking in ours values gain forty five minutes four suggest nine word forty two and also you desire to find position of being big at what quarter of a second point two 5 zero seconds. Feather this in for tea positions forty suggest nine meter at a quarter of a second, eh? and also then finding its position one second after the was possible horizontally. Last position. Forty suggest one meters. Now, Harvey, that's a fine. Just how long the takes for the being huge hits the ground five minutes. He just said The over equation equals zero in the quadratic formula and selling for tea you get it access time the ground. Three point four one seconds later. Following you desire to uncover the final velocity as soon as hits the soil on a velocity is simply provided by early stage velocity. What's the acceleration? time Time? Oh, our final velocity is same to 5 on its nine suggest eight. I'm three point for one. There to be a time, a velocity of an unfavorable twenty eight suggest four seconds. Now Hardy asked united state to uncover Mac exactly how long it takes until the bean big regions of Mac it's preferably height characterized this. We think about that at the top of its gift baked trajectory, the velocity zero friends, intentions moment, it appears they're going up or down. So WeII said, Finally, we call fifty percent of the trajectory that the height of the trajectory. We say the that's our last velocity. It's about equal zero. And then course, yeah, the equation we're utilizing is when again the of finding the final velocity. And also the 5 lakhs equals zero the the initially 5 has provided on nine allude eight fine that the beanbag reaches its maximum elevation at zero point five seconds. Finally, component e were struck. 3 graphs. Very first one, it's the acceleration, very first time, and also the acceleration is constant. It's just grab these. This is just going to it is in a right line, actually. The method we defined it with confident by going increase the acceleration an adverse of a better line. Time acceleration, andare explorations be constant. An adverse nine point eight meters. Oh, the wind velocity verse time. What velocity starts out positive, yet then ultimately finished his negative. It's gonna look like this just straight bottom sloping line. Finally, that position. Why place as a function of time going to it is in a rabble the quadratic and it's gonna just boost up a tiny bit. Acquire maximum height type search sloping down.