a) $-4.80 mathrmm / mathrms$b) $t=3.41 mathrms$c) $-28.4 mathrmm / mathrms$d) $1.28 mathrmm$e) The graphs of $a_y, v_y,$ and also $y$ versus $t$ are provided in Figure $2.44 .$ Take $y=0$ at the ground.




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Video Transcript

Okay, so we have a warm air balloon increasing at five meters per second at a height of forty meters off the ground and as soon as at a elevation of forty meters off the ground dwellings. Beanbag. We desire to discover the place of this bean bag after so unparticular times. So we first use position is a function of time equation for why Oh, Titian. At any kind of time T is offered by the initial place. What's the initial velocity time? US one have acceleration times, times squared. Looking in our values obtain forty five minutes 4 point nine word forty 2 and also you desire to discover place of being massive at what quarter of a second point two five zero seconds. Looking this in for tea positions forty suggest nine meters at a quarter of a second, eh? And then finding its place one second after it was feasible horizontally. Final position. Forty suggest one meters. Now, Harvey, that's a fine. How lengthy it takes for the being huge hits the ground 5 minutes. He simply sassist The above equation amounts to zero in the quadratic formula and also selling for tea you acquire it hits the ground. Three point four one secs later. Next off you desire to uncover the final velocity as soon as hits the ground on a velocity is simply given by initial velocity. What's the acceleration? Times Time? Oh, our last velocity is equal to five on its nine point eight. I'm three suggest for one. Tbelow was a time, a velocity of negative twenty eight point four seconds. Now Hardy asked us to uncover Mac how lengthy it takes until the bean big areas of Mac it's maximum height characterized this. We consider that at the height of its being baked trajectory, its velocity zero friends, intentions minute, it appears they're going up or dvery own. So WeII sassist, Finally, we contact fifty percent of the trajectory of the optimal of the trajectory. We say that that's our last velocity. It's about equal zero. And then course, yeah, the equation we're using is once aacquire that of finding the final velocity. And the five lakhs equals zero of the initially 5 has actually offered on nine point eight fine that the beanbag reaches its maximum elevation at zero allude 5 seconds. Finally, component e were struck. Three graphs. First one, it's the acceleration, initially time, and also the acceleration is constant. It's simply grab these. This is simply going to be a directly line, actually. The method we identified it via positive by going up the acceleration negative of a far better line. Time acceleration, andare explorations be constant. Negative nine point eight meters. Oh, the wind velocity verse time. What velocity starts out positive, but then eventually finimelted his negative. It's gonna look favor this simply directly downward sloping line. Finally, its position. Why position as a function of time going to be a rabble of quadratic and also it's gonna just increase up a little little. Get maximum height develop search sloping down.