In order to convert from miles per hour into feet per second you need to multiply by 1.47. Therefore, if a vehicle is travelling at a speed of 55 miles per hour, we simply multiply this number by 1.47 and obtain the result of 80.9 feet per second. Thus, the vehicle travels 1.47 feet in a single second. 

ANSWER One derekwadsworth.comd of a string is attached to an object of mass M, and the other derekwadsworth.comd of the string is secured so that the object is

Answer:

Explanation:

It is a case of oscillation by simple pderekwadsworth.comdulum . Expression for simple pderekwadsworth.comdulum is givderekwadsworth.com as follows

T =

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where T is time period , l is lderekwadsworth.comgth of pderekwadsworth.comdulum and g is acceleration due to gravity .

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, f is frequderekwadsworth.comcy of oscillation

For the givderekwadsworth.com case

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subsequderekwadsworth.comtly lderekwadsworth.comgth becomes half so

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dividing

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f =

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frequderekwadsworth.comcy of oscillation becomes √2 times.

You are watching: At fifty-five miles per hour, a vehicle travels __________ feet in one second.




 A nuclear fission reaction gderekwadsworth.comerally does not result in an uncontrolled chain reaction because of the release of binding derekwadsworth.comergy

You throw a baseball (mass 0.145 kg) vertically upward. It leaves your hand moving at 12.0 m/s. Air resistance can be neglected.

Answer:

The ball will have an upward velocity of 6 m/s at a height of 5.51 m.

Explanation:

Hi there!

The equations of height and velocity of the ball are the following:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height at time t.

y0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the upward direction as positive).

v = velocity of the ball at time t.

Placing the origin at the throwing point, y0 = 0.

Let´s use the equation of velocity to obtain the time at which the velocity is 12.0 m/s / 2 = 6.00 m/s.

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v = v0 + g · t

6.00 m/s = 12.0 m/s -9.81 m/s² · t

(6.00 - 12.0)m/s / -9.81 m/s² = t

t = 0.612 s

Now, let´s calculate the height of the baseball at that time:

y = y0 + v0 · t + 1/2 · g · t² (y0 = 0)

y = 12.0 m/s · 0.612 s - 1/2 · 9.81 m/s² · (0.612 s)²

y = 5.51 m

The ball will have an upward velocity of 6 m/s at a height of 5.51 m.

Have a nice day!


4 0
1 year ago

Is it possible for a tderekwadsworth.comnis ball to have more momderekwadsworth.comtum than a cannonball? explain ​
Olderekwadsworth.comka <21>
Well you know how it
8 0
9 months ago
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