In bespeak to transform from miles every hour right into feet per 2nd you should multiply by 1.47. Therefore, if a vehicle is travelling at a rate of 55 miles every hour, we just multiply this number by 1.47 and obtain the an outcome of 80.9 feet per second. Thus, the vehicle travels 1.47 feet in a single second. 

ANSWER One derekwadsworth.comd the a wire is fastened to things of mass M, and also the other derekwadsworth.comd that the string is secured so that the object is

Answer:

Explanation:

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You are watching: At fifty-five miles per hour, a vehicle travels __________ feet in one second.




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You litter a baseball (mass 0.145 kg) vertically upward. It pipeline your hand moving at 12.0 m/s. Waiting resistance have the right to be neglected.

Answer:

The sphere will have an upward velocity of 6 m/s in ~ a elevation of 5.51 m.

Explanation:

Hi there!

The equations the height and also velocity the the ball space the following:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height at time t.

y0 = early stage height.

v0 = early velocity.

t = time.

g = acceleration due to gravity (-9.81 m/s² considering the increase direction together positive).

v = velocity that the round at time t.

Placing the origin at the throw point, y0 = 0.

Let´s usage the equation that velocity to achieve the time at which the velocity is 12.0 m/s / 2 = 6.00 m/s.

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v = v0 + g · t

6.00 m/s = 12.0 m/s -9.81 m/s² · t

(6.00 - 12.0)m/s / -9.81 m/s² = t

t = 0.612 s

Now, let´s calculate the height of the baseball at that time:

y = y0 + v0 · t + 1/2 · g · t² (y0 = 0)

y = 12.0 m/s · 0.612 s - 1/2 · 9.81 m/s² · (0.612 s)²

y = 5.51 m

The round will have actually an increase velocity of 6 m/s at a elevation of 5.51 m.

Have a pretty day!


4 0
1 year ago

Is it possible for a tderekwadsworth.comnis sphere to have more momderekwadsworth.comtum 보다 a cannonball? define ​
Olderekwadsworth.comka <21>
Well girlfriend know exactly how it
8 0
9 months ago
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