We must usage the equation for the time of flight, yet we do not have actually v0. We can uncover v0 from the expression for array as:

v0=Rgsin(2θ)=(220)(9.8)sin<(2)(45°)>

v0 =46.43 m/s


*

An arrowhead is shot at an angle of θ = 45° over the horizontal. The arrowhead hits a tree a horizontal distance D = 220m amethod, at the same elevation above the ground as it was swarm. The height from which the arrowhead is shot is 6 m. Use g=9.8m/s2 for the magnitude of the acceleration due to gravity.

You are watching: An arrow is shot at an angle of θ=45∘ above the horizontal

Part A

Find ta, the moment that the arrowhead spends in the air.

Part B

How lengthy after the arrow was shot need to the apple be dropped, in order for the arrow to pierce the apple as the arrow hits the tree?


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What scientific principle carry out you have to know in order to settle this problem?

Our tutors have actually shown that to resolve this problem you will must use the Symmetrical Launch principle. You have the right to view video lessons to learn Symmetrical Launch. Or if you need even more Symmetrical Launch exercise, you deserve to additionally practice Symmetrical Launch practice problems.


What professor is this problem pertinent for?

Based on our information, we think this difficulty is relevant for Professor Blake's class at MC MARICOPA.

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