L> Solenoids as Magnetic Field SourcesSolenoid

A long directly coil of wire deserve to be used to generate a practically unidevelop magnetic area comparable to that of a bar magnet. Such coils, dubbed solenoids, have actually an enormousvariety of useful applications. The field canbe significantly strengthenedby the enhancement ofan iron core.Such cores aretypical inelectromagnets. In the over expression for the magnetic field B, n = N/L is the number of transforms per unit length, occasionally called the "transforms density". The magnetic area B is proportional to the present I in the coil. The expression is an idealization to an unlimited size solenoid, however gives a good approximation to the field of a long solenoid.

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Go BackSolenoid Field from Ampere"s LawTaking a rectangular route about which to evaluate Ampere"s Law such that the size of the side parallel to the solenoid area is L
offers a contribution BL inside the coil.The area is essentially perpendicular tothe sides of thecourse, giving negligible contribution. If thefinish is taken so far from the coil that thefield is negligible, thenthe length inside the coilis the leading contribution. This admittedly idealized instance for Ampere"s Law gives This turns out to be an excellent approximation for the solenoid field, specifically in the instance of an iron core solenoid.
 Solenoid discussion Calculate field
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Go BackSolenoid Magnetic Field Calculation

 At the center of a long solenoid  Active formula: click on the quantity you wish to calculate. Magnetic area = permeability x rotate density x existing
feature bcal()fh=document.forms<0>;def();nn=fh.nl.value;ii=fh.i.value;mm=4*Math.PI*Math.pow(10,-7);kk=fh.k.value;bb=mm*kk*nn*ii;fh.b.value=display(bb);fh.bg.value=display(10000*bb)function pcal()fh=document.forms<0>;def();nn=fh.nl.value;ii=fh.i.value;mm=4*Math.PI*Math.pow(10,-7);bb=fh.b.value;kk=bb/(mm*nn*ii);fh.k.value=kkfeature ical()fh=document.forms<0>;def();nn=fh.nl.value;bb=fh.b.value;mm=4*Math.PI*Math.pow(10,-7);kk=fh.k.value;ii=bb/(mm*kk*nn);fh.i.value=iifeature ncal()fh=record.forms<0>;def();bb=fh.b.value;ii=fh.i.value;mm=4*Math.PI*Math.pow(10,-7);kk=fh.k.value;nnl=bb/(mm*kk*ii);fh.nl.value=nnl;fh.n.value=fh.l.value*nnlfunction ul(l)fh=record.forms<0>;def();fh.nl.value=fh.n.value/lattribute un(nn)fh=record.forms<0>;def();fh.nl.value=nn/fh.l.valuefunction unl(nnl)fh=record.forms<0>;def();fh.n.value=fh.l.value*nnlfeature ub(bb)fh=record.forms<0>;def();fh.bg.value=display(bb*10000)function ubg(gg)fh=document.forms<0>;def();fh.b.value=display(gg/10000)attribute def()fh=record.forms<0>;if (fh.i.value==0)fh.i.value=1;if (fh.l.value==0)fh.l.value=.1;if (fh.n.value==0)fh.n.value=100;if (fh.nl.value==0)fh.nl.value=1000;if (fh.b.value==0)fh.b.value=.1;if (fh.k.value==0)fh.k.value=200attribute display(x)xx=x;if(x.99*Math.pow(10,6))xx="...";rerotate xx

For a solenoid of length L = m through N = turns, the revolve density is n=N/L= turns/m.

If the present in the solenoid is I = amperes

and the relative permecapacity of the core is k = ,

then the magnetic area at the center of the solenoid is

B = Tesla = gauss.

The Earth"s magnetic area is around half a gauss.

The relative permecapability of magnetic iron is around 200.

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Get in data, then click on the amount you wish to calculate in the energetic formula over the information enattempt points. Default values will certainly be entered for unstated parameters, yet the numbers will not be required to be continual until you click the quantity to calculate.

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