L> Solenoids together Magnetic field SourcesSolenoid

A long straight coil that wire have the right to be supplied to generate a virtually uniform magnetic field comparable to the of a bar magnet. Such coils, called solenoids, have actually an enormousnumber of useful applications. The field canbe significantly strengthenedby the enhancement ofan iron core.Such cores aretypical inelectromagnets.

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In the over expression for the magnetic ar B, n = N/L is the variety of turns per unit length, sometimes referred to as the "turns density". The magnetic ar B is proportional to the existing I in the coil. The expression is one idealization come an boundless length solenoid, but provides a an excellent approximation to the ar of a long solenoid.

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Derive ar expressionCalculate fieldField of current loop
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Go BackSolenoid ar from Ampere"s LawTaking a rectangular path about which to advice Ampere"s regulation such that the length of the side parallel to the solenoid ar is l
offers a donation BL inside the coil.The ar is essentially perpendicular tothe political parties of thepath, giving negligible contribution. If theend is bring away so far from the coil that thefield is negligible, thenthe length inside the coilis the leading contribution.
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This admittedly idealized instance for Ampere"s law gives

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This transforms out to it is in a good approximation for the solenoid field, an especially in the instance of one iron core solenoid.

Solenoid discussionCalculate field
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Go BackSolenoid Magnetic ar Calculation

At the center of a long solenoid
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Active formula: click on the amount you great to calculate. Magnetic field = permeability x turn thickness x current
function bcal()fh=document.forms<0>;def();nn=fh.nl.value;ii=fh.i.value;mm=4*Math.PI*Math.pow(10,-7);kk=fh.k.value;bb=mm*kk*nn*ii;fh.b.value=display(bb);fh.bg.value=display(10000*bb)function pcal()fh=document.forms<0>;def();nn=fh.nl.value;ii=fh.i.value;mm=4*Math.PI*Math.pow(10,-7);bb=fh.b.value;kk=bb/(mm*nn*ii);fh.k.value=kkfunction ical()fh=document.forms<0>;def();nn=fh.nl.value;bb=fh.b.value;mm=4*Math.PI*Math.pow(10,-7);kk=fh.k.value;ii=bb/(mm*kk*nn);fh.i.value=iifunction ncal()fh=document.forms<0>;def();bb=fh.b.value;ii=fh.i.value;mm=4*Math.PI*Math.pow(10,-7);kk=fh.k.value;nnl=bb/(mm*kk*ii);fh.nl.value=nnl;fh.n.value=fh.l.value*nnlfunction ul(l)fh=document.forms<0>;def();fh.nl.value=fh.n.value/lfunction un(nn)fh=document.forms<0>;def();fh.nl.value=nn/fh.l.valuefunction unl(nnl)fh=document.forms<0>;def();fh.n.value=fh.l.value*nnlfunction ub(bb)fh=document.forms<0>;def();fh.bg.value=display(bb*10000)function ubg(gg)fh=document.forms<0>;def();fh.b.value=display(gg/10000)function def()fh=document.forms<0>;if (fh.i.value==0)fh.i.value=1;if (fh.l.value==0)fh.l.value=.1;if (fh.n.value==0)fh.n.value=100;if (fh.nl.value==0)fh.nl.value=1000;if (fh.b.value==0)fh.b.value=.1;if (fh.k.value==0)fh.k.value=200function display(x)xx=x;if(x.99*Math.pow(10,6))xx="...";return xx

For a solenoid of size L = m v N = turns, the turn thickness is n=N/L= turns/m.

If the existing in the solenoid is ns = amperes

and the relative permeability the the core is k = ,

then the magnetic ar at the facility of the solenoid is

B = Tesla = gauss.

The Earth"s magnetic ar is about half a gauss.

The relative permeability the magnetic steel is around 200.

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Enter data, then click the quantity you great to calculation in the active formula above the data entry points. Default values will be gone into for unspecified parameters, however the numbers will certainly not be required to be continual until you click on the quantity to calculate.

Solenoid discussionDerive ar expressionRelative permeability
IndexMagnetic field conceptsCurrents as magnetic sources
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